9x^2+54x-9=0

Solution for 9x^2+54x-9=0 equation:

9x^2+54x-9=0

a = 9; b = 54; c = -9;
Δ = b2-4ac
Δ = 542-4·9·(-9)
Δ = 3240
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3240}=\sqrt{324*10}=\sqrt{324}*\sqrt{10}=18\sqrt{10}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(54)-18\sqrt{10}}{2*9}=\frac{-54-18\sqrt{10}}{18}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(54)+18\sqrt{10}}{2*9}=\frac{-54+18\sqrt{10}}{18}
$